AP EAMCET · Maths · Complex Number
If \(\frac{2+3 i \sin \theta}{1-2 i \sin \theta}\) is purely imaginary, then \(\cos ^2 \theta=\)
- A \(\frac{1}{2}\)
- B \(\frac{3}{2}\)
- C \(\frac{1}{3}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{2}{3}\)
Step-by-step Solution
Detailed explanation
Real part \( = \frac{2(1) + (3 \sin \theta)(-2 \sin \theta)}{1^2 + (-2 \sin \theta)^2} = \frac{2-6\sin^2\theta}{1+4\sin^2\theta} \) For purely imaginary, \( 2-6\sin^2\theta = 0 \) \( \sin^2\theta = \frac{2}{6} = \frac{1}{3} \)…
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