AP EAMCET · Maths · Continuity and Differentiability
Find the value of for which the function is continuous.
- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
For this function to be continuous limx→0eαx−ex−xx2=32, it is 00 form Now, applying L'Hospital rule, limx→0αeαx−ex−12x=αeα0−e0−12x Now, as denominator gives the value 0. In order for the…
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