AP EAMCET · Maths · Vector Algebra
Let \(\mathbf{u}\) and \(\mathbf{v}\) be two non-zero vectors. Then the magnitude of the cross product \(\mathbf{u} \times \mathbf{v}\) is always
- A \( < |u||v|\)
- B \(=|u||v|\)
- C \(>|u||v|\)
- D \(=0\)
Answer & Solution
Correct Answer
(A) \( < |u||v|\)
Step-by-step Solution
Detailed explanation
The cross product of \(u\) and \(v\) non-zero vectors is \(\mathbf{u} \times \mathbf{v}=|\mathbf{u} \| \mathbf{v}| \sin \theta \hat{\mathbf{n}}\), if angle between them is \(\theta\). So, \(\quad|u \times v|=|u||v||\sin \theta|\)…
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