AP EAMCET · PHYSICS · Thermal Properties of Matter
The walls of a closed cubical box of edge \(60 \mathrm{~cm}\) are made of material of thickness \(1 \mathrm{~mm}\) and thermal conductivity, \(4 \times 10^{-4} \mathrm{cal} \mathrm{s}^{-1} \mathrm{~cm}^{-1}{ }^{\circ} \mathrm{C}^{-1}\). The interior of the box is maintained \(1000^{\circ} \mathrm{C}\) above the outside temperature by a heater placed inside the box and connected across \(400 \mathrm{~V}\) DC supply. The resistance of the heater is
- A \(4.41 \Omega\)
- B \(44.1 \Omega\)
- C \(0.441 \Omega\)
- D \(441 \Omega\)
Answer & Solution
Correct Answer
(C) \(0.441 \Omega\)
Step-by-step Solution
Detailed explanation
Key Idea Heat transfer through conduction wall is given by mathematical expression, \[ \frac{d Q}{d t}=k A \frac{\left(T_1-T_0\right)}{x} \] where, \(\frac{d Q}{d t}=\) power transferred through the wall and \(x=\) thickness of the wall Here, side of cube, \(a=60 \mathrm{~cm}\).…
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