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AP EAMCET · Maths · Straight Lines

In \(\triangle \mathrm{ABC}\) the coordinates of the vertex \(\mathrm{A}\) are \((-3,1)\). If the equation of the median through \(B\) is \(2 x+y-3=0\) and the equation of the bisector of angle \(\mathrm{C}\) is \(7 \mathrm{x}-4 \mathrm{y}-1=0\), then the equation of the side \(\mathrm{BC}\) is

  1. A \(7 x-3 y=6\)
  2. B \(18 \mathrm{x}-\mathrm{y}=49\)
  3. C \(15 x+y=50\)
  4. D \(4 x-y=7\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(18 \mathrm{x}-\mathrm{y}=49\)

Step-by-step Solution

Detailed explanation

\(M=\) Mid point of \(A C=\left(\frac{-3+h}{2}, \frac{1+k}{2}\right)\) \(\because(h, k)\) lies on \(7 x-4 y-1=0\). \(\Rightarrow 7 h-4 k-1=0 \Rightarrow h=\frac{4 k+1}{7}\)…