AP EAMCET · Maths · Ellipse
If the lines joining the origin to the points of intersection of \(2 x+3 y=k\) and \(3 x^2-x y+3 y^2+2 x-3 y-4=0\) are at right angles, then
- A \(6 \mathrm{k}^2+5 \mathrm{k}+52=0\)
- B \(6 \mathrm{k}^2+5 \mathrm{k}-52=0\)
- C \(6 \mathrm{k}^2-5 \mathrm{k}+52=0\)
- D \(6 \mathrm{k}^2-5 \mathrm{k}-52=0\)
Answer & Solution
Correct Answer
(D) \(6 \mathrm{k}^2-5 \mathrm{k}-52=0\)
Step-by-step Solution
Detailed explanation
Given line \(2 x+3 y=k\) \[ \Rightarrow \frac{2 x+3 y}{k}=1 ...(i) \] Also given, \(3 x^2-x y+3 y^2+2 x-3 y-4=0\) Now homogenising the above equation…
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