AP EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C\), if \(\angle A=60^{\circ}\), then \(\frac{b}{c+a}+\frac{c}{a+b}=\)
- A \(a+b+c\)
- B 0
- C 1
- D \(a b c\)
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
Apply cosine rule, \(\cos A=\frac{b^2+c^2-a^2}{2 b c}\) Here, \(A=60^{\circ}\)…
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