AP EAMCET · Maths · Properties of Triangles
In \(\triangle \mathrm{ABC}\), if \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) are in arithmetic progression, then \(\frac{\mathrm{c}}{\mathrm{a}} \sin 2 \mathrm{~A}+\frac{\mathrm{a}}{\mathrm{c}} \sin 2 \mathrm{C}=\)
- A \(\frac{\sqrt{3}}{2}\)
- B \(\sqrt{3}\)
- C 1
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{3}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {} \because A, B, C \text { are in A.P } \\ & \therefore 2 B=A+C \\ & \text { Now, } A+B+C=180 \Rightarrow 3 B=180 \Rightarrow B=60^{\circ} \\ & \frac{c}{a} \sin 2 A+\frac{a}{c} \sin 2 C=\frac{c}{a} \times 2 \sin A \cos A+\frac{a}{c} \times 2 \sin C \cos…
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