AP EAMCET · PHYSICS · Alternating Current
An ac voltage of \(10 \sin \omega t\) volt is applied to a pure inducfor of inductance \(10 \mathrm{H}\). The current through the inductor in ampere is
- A \(\frac{1}{\theta} \sin \left(\omega t-\frac{\pi}{2}\right)\)
- B \(\omega \sin \left(\omega t-\frac{\pi}{2}\right)\)
- C \(\frac{1}{\omega^2} \sin \left(\omega t-\frac{\pi}{2}\right)\)
- D \(\omega^2 \sin \left(\omega t-\frac{\pi}{2}\right)\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\theta} \sin \left(\omega t-\frac{\pi}{2}\right)\)
Step-by-step Solution
Detailed explanation
Apply the kirchhoff's loop rule \[ \begin{aligned} & V+E=0 \\ & V-L \frac{d i}{d t}=0 \\ & V=L \frac{d i}{d t} \end{aligned} \]…
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