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AP EAMCET · Maths · Determinants

If A, B, C are the angles of a triangle then the system of equations -x+ycosC+zcosB=0, xcosC-y+zcosA=0, xcosB+ycosA-z=0 have

  1. A only zero solution
  2. B a non-zero solution for all triangles ABC
  3. C only zero solution but for certain values of A, B, C
  4. D a non-zero solution if ABC is an equilateral triangle & not for all triangles
Verified Solution

Answer & Solution

Correct Answer

(D) a non-zero solution if ABC is an equilateral triangle & not for all triangles

Step-by-step Solution

Detailed explanation

A,B,C are angles of triangle. -x+ycosC+zcosB=0 xcosC-y+zcosA=0 xcosB+ycosA-z=0 A=-1cosCcosBcosC-1cosAcosBcosA-1 A=-11-cos2A-cosC-cosC-cosA.cosB+cosBcosA.cosC+cosB A=-1+cos2A+cos2C+cosA.cosB.cosC+cosA.cosB.cosC+cos2B ∵A,B, C are angles of triangle. So, A=0 for…
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