AP EAMCET · Maths · Straight Lines
A circle having centre at the origin passes through the three vertices of an equilateral triangle the length of its median being 9 units. Then the equation of that circle is
- A \(x^2+y^2=9\)
- B \(x^2+y^2=18\)
- C \(x^2+y^2=36\)
- D \(x^2+y^2=81\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2=36\)
Step-by-step Solution
Detailed explanation
We have, length of median of \(\triangle A B C=9\) \[ \therefore \quad A O=\frac{2}{3} A D \Rightarrow A O=\frac{2}{3} \times 9=6 \] \(O\) is the circumcentre of \(\triangle A B C\). We know that in equilateral triangle circumcentre, incentre, centroid coincide.…
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