AP EAMCET · Maths · Application of Derivatives
If the distance \(s\) described in time ' \(t\) ' by a particle moving on a straight line is given by \(s=t^5-40 t^3+30 t^2+80 t-250\), then its minimum acceleration is
- A 260
- B -260
- C 130
- D -130
Answer & Solution
Correct Answer
(B) -260
Step-by-step Solution
Detailed explanation
Given that, \(S=t^5-40 t^3+30 t^2+80 t-250\) \[ \begin{aligned} & V=\frac{d S}{d t}=5 t^4-120 t^2+60 t+80 \\ & a=\frac{d V}{d t}=\frac{d^2 S}{d t^2}=20 t^3-240 t+60 \end{aligned} \] Let…
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