AP EAMCET · Maths · Complex Number
If \(-3+i x^2 y\) and \(x^2+y+4 i\) are complex conjugates, then \(\mathrm{x}=\)
- A 0
- B \(\pm 1\)
- C \(\pm 3\)
- D \(\pm 4\)
Answer & Solution
Correct Answer
(B) \(\pm 1\)
Step-by-step Solution
Detailed explanation
\(\because-3+\mathrm{ix}^2 \mathrm{y}\) and \(\left(\mathrm{x}^2+\mathrm{y}+4 \mathrm{i}\right)\) are complex conjugate. Then, \(-3-i x^2 y=x^2+y+4 i\) Comparing both sides we get:- \[ \begin{aligned} & x^2+y=-3 ......(i)\\ & -x^2 y=4.......(ii) \end{aligned} \] Solving eqs. (i)…
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