AP EAMCET · Maths · Properties of Triangles
In \(\triangle \mathrm{ABC}\), if \(\triangle \mathrm{A}=90^{\circ}\), then \(2(r+\mathrm{R})=\)
- A \(a+b\)
- B \(b+c\)
- C \(c+a\)
- D \(a+b+c\)
Answer & Solution
Correct Answer
(B) \(b+c\)
Step-by-step Solution
Detailed explanation
\(R=\frac{a}{2}\) \(r=\frac{b+c-a}{2}\) \(2(r+R) = 2\left(\frac{b+c-a}{2} + \frac{a}{2}\right)\) \(2(r+R) = b+c-a+a\) \(2(r+R) = b+c\)
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