AP EAMCET · Maths · Probability
A manufacturing company noticed that \(1 \%\) of its products are defective. If a dealer orders for 300 items from this company, then the probability that the number of defective items is atmost one is
- A \(\frac{3}{e^3}\)
- B \(\frac{2}{e^3}\)
- C \(\frac{3}{e^2}\)
- D \(\frac{4}{e^3}\)
Answer & Solution
Correct Answer
(D) \(\frac{4}{e^3}\)
Step-by-step Solution
Detailed explanation
\(n=300, p=0.01\) \(m=\) mean number of defective items \(\Rightarrow m=n p=3\) Since p is small, we can use poison's distribution…
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