AP EAMCET · Maths · Circle
In a square \(A B C D\) of side length \(a\), suppose \(A B\) and \(A D\) are along the coordinate axes. Then, the circle that circumscribes the square is
- A \(x^2+y^2+a(x+y)=0\)
- B \(x^2+y^2-a(x+y)=0\)
- C \(x^2+y^2+2 a(x+y)=0\)
- D \(x^2+y^2-2 a(x+y)=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-a(x+y)=0\)
Step-by-step Solution
Detailed explanation
\(B D\) is diameter. \(\therefore\) Circle is \[ \begin{array}{rr} & (x-0)(x-a)+(y-a)(y-0)=0 \\ \Rightarrow & x^2+y^2-a(x+y)=0 \end{array} \]
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