AP EAMCET · Maths · Functions
Let \(\mathbb{N}\) be the set of all natural numbers and \(f: \mathbb{N} \rightarrow \mathbb{N}\) be such that \(1990 < \mathrm{f}(1990) < 2100\) and satisfies the equation \(x-f(x)=19\left[\frac{x}{19}\right]-90\left[\frac{f(x)}{90}\right] \text {, }\) where \([y]\) denotes the greatest integer less than or equal to \(y\). Then the number of possible values of \(f(1990)\) is
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
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