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AP EAMCET · Maths · Circle

A line \(l\) meets the circle \(x^2+y^2=61\) in \(A, B\) and \(P(-5,6)\) is such that \(P A=P B=10\). Then, the equation of \(l\) is

  1. A \(5 x+6 y+11=0\)
  2. B \(5 x-6 y-11=0\)
  3. C \(5 x-6 y+11=0\)
  4. D \(5 x-6 y+12=0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5 x-6 y+11=0\)

Step-by-step Solution

Detailed explanation

Since, the line \(l\) meets the circle \(x^2+y^2=61\) at two points \(A\) and \(B\). \[ \because P A=P B=10 \] \(\therefore P M\) is perpendicular to \(A B\) and \(O M\) is perpendicular to the chord \(A B\), therefore line \(O P\) is perpendicular to \(A B\). \(\therefore\) The…