AP EAMCET · Maths · Vector Algebra
If \(\vec{a}, \vec{b}\) are two unit vectors with \((\vec{a}, \vec{b})=\theta\) and \(|\vec{a}-\vec{b}|=1\), then \(2|\vec{a}+\vec{b}| \cos \frac{\theta}{2}=\)
- A 3
- B 1
- C \(\sqrt{3}\)
- D 9
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \because \quad \vec{a}, \vec{b} \text { are unit vectors. So, }|\vec{a}|=1 \&|\vec{b}|=1 \\ & \text { Also, }|\vec{a}-\vec{b}|^2=1 \Rightarrow|\vec{a}-\vec{b}|^2=1 \\ & \Rightarrow|\vec{a}|^2+|\vec{b}|^2-2 \vec{a} \cdot \vec{b}=1 \\ & \Rightarrow…
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