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AP EAMCET · Maths · Straight Lines

The line \(x+y=1\) meets the lines represented by the equation \(y^3-6 x y^2+11 x^2 y-6 x^3=0\) at the points \(P, Q, R\). If \(O\) is the origin, then \((O P)^2+(O Q)^2+(O R)^2=\)

  1. A \(\frac{85}{72}\)
  2. B \(\frac{121}{72}\)
  3. C \(\frac{212}{72}\)
  4. D \(\frac{217}{72}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{121}{72}\)

Step-by-step Solution

Detailed explanation

We are given with a cubic equation which represents 3-lines. Let lines have, \(y-m_1 x=0 ; y-m_2 x=0\) and \(y-m_3 x=0\) Then, \(\left(y-m_1 x\right)\left(y-m_2 x\right)\left(y-m_3 x\right)=0\) is the combined equations Which in this case is, \(y^3-6 x y^2+11 x^2 y-6 x^3=0\) By…
From AP EAMCET
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