AP EAMCET · Maths · Quadratic Equation
If \(y^2+z^2=a y z, z^2+x^2=b x z, x^2+y^2=c x y\), then the value of \(\frac{x z}{y^2}+\frac{y^2}{z x}\) is
- A \(a^2-b^2+c^2\)
- B \(a^2+b^2+c^2\)
- C \(a c-b\)
- D \(a b-c\)
Answer & Solution
Correct Answer
(C) \(a c-b\)
Step-by-step Solution
Detailed explanation
\(\because y^2+z^2=a y z\) \(\Rightarrow \quad \frac{y^2+z^2}{y z}=\frac{a y z}{y z}\) \(\Rightarrow \quad \frac{y}{z}+\frac{z}{y}=a\) ...(i) \(\because \quad z^2+x^2=b z x\) \(\Rightarrow \quad \frac{z}{x}+\frac{x}{z}=b\) ...(ii) and \(\quad x^2+y^2=c x y\)…
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