AP EAMCET · Maths · Vector Algebra
Let \(\vec{a}, \vec{b}, \vec{c}\) be three vectors such that \(\vec{a}\) is perpendicular to \(\overrightarrow{\mathrm{b}}\) and \(\overrightarrow{\mathrm{b}}\) is perpendicular to \(\overrightarrow{\mathrm{c}}\). If \(|\overrightarrow{\mathrm{a}}|=2,|\overrightarrow{\mathrm{b}}|=3,|\overrightarrow{\mathrm{c}}|=5\) and \(|\vec{a}+\vec{b}+\vec{c}|=4 \sqrt{3}\), then the angle between \(\vec{a}\) and \(\vec{c}\) is
- A \(\cos ^{-1} \frac{2}{5}\)
- B \(\frac{\pi}{3}\)
- C \(\cos ^{-1}\left(\frac{2}{3}\right)\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
Given that \(\vec{a} \cdot \vec{b}=0, \vec{b} \cdot \vec{c}=0,|\vec{a}|=2,|\vec{b}|=3\)…
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