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AP EAMCET · Maths · Binomial Theorem

If \(|x| \lt \frac{2}{2}\) then the \(4^{\text {th }}\) term in the expansion of \((3 x-2)^{2 / 3}\) is

  1. A \(\frac{\sqrt[3]{4}}{6} x^3\)
  2. B \(-\frac{\sqrt[3]{4}}{6} x^3\)
  3. C \(\frac{\sqrt[3]{4}}{8} x^3\)
  4. D \(-\frac{\sqrt[3]{4}}{8} x^3\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-\frac{\sqrt[3]{4}}{6} x^3\)

Step-by-step Solution

Detailed explanation

\((3 x-2)^{\frac{2}{3}}=\left[-2\left(1-\frac{3 x}{2}\right)\right]^{\frac{2}{3}}=(-2)^{\frac{2}{3}}\left(1-\frac{3 x}{2}\right)^{\frac{2}{3}}\)…