AP EAMCET · Maths · Binomial Theorem
If \(|x| \lt \frac{2}{2}\) then the \(4^{\text {th }}\) term in the expansion of \((3 x-2)^{2 / 3}\) is
- A \(\frac{\sqrt[3]{4}}{6} x^3\)
- B \(-\frac{\sqrt[3]{4}}{6} x^3\)
- C \(\frac{\sqrt[3]{4}}{8} x^3\)
- D \(-\frac{\sqrt[3]{4}}{8} x^3\)
Answer & Solution
Correct Answer
(B) \(-\frac{\sqrt[3]{4}}{6} x^3\)
Step-by-step Solution
Detailed explanation
\((3 x-2)^{\frac{2}{3}}=\left[-2\left(1-\frac{3 x}{2}\right)\right]^{\frac{2}{3}}=(-2)^{\frac{2}{3}}\left(1-\frac{3 x}{2}\right)^{\frac{2}{3}}\)…
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