AP EAMCET · Maths · Trigonometric Equations
If \(\frac{x}{\cos \alpha}=\frac{y}{\cos \left(\frac{2 \pi}{3}-\alpha\right)}=\frac{z}{\cos \left(\frac{2 \pi}{3}+\alpha\right)}\), then the value of \((x+y+z)\) is equal to
- A \(\frac{1}{2}\)
- B 0
- C 1
- D 2
Answer & Solution
Correct Answer
(B) 0
Step-by-step Solution
Detailed explanation
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