AP EAMCET · Maths · Straight Lines
If \(t \in \mathbb{R}-\{-1\}\), then the locus of the point \(\left(\frac{3 a t}{1+t^3}, \frac{3 \mathrm{at}^2}{1+t^3}\right)\) is
- A \(\mathrm{x}^3+\mathrm{y}^3=3 a \mathrm{x}^2 \mathrm{y}^2\)
- B \(x^3-3 a x^2 y-3 a x y^2+y^3=0\)
- C \(x^3+y^3=3 a x y\)
- D \(x^3-y^3=3 a x y\)
Answer & Solution
Correct Answer
(C) \(x^3+y^3=3 a x y\)
Step-by-step Solution
Detailed explanation
Here, \(x=\frac{3 a t}{1+t^3}, y=\frac{3 a t^2}{1+t^3}\)…
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