AP EAMCET · Maths · Quadratic Equation
If \(x\) is real, then the minimum value of \(y=\frac{x^2-x+1}{x^2+x+1}\) is
- A \(3\)
- B \(\frac{1}{3}\)
- C \(\frac{1}{3}\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
Let \(y=\frac{1-x+x^2}{1+x+x^2}\) On differentiating w.r.t. \(x\), we get…
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