AP EAMCET · Maths · Mathematical Induction
\(\sum_{n=1}^5 n\left(n^2+n+1\right)=\)
- A 500
- B 155
- C 295
- D 395
Answer & Solution
Correct Answer
(C) 295
Step-by-step Solution
Detailed explanation
\(\sum_{n=1}^5 n(n^2+n+1) = 1(1^2+1+1) + 2(2^2+2+1) + 3(3^2+3+1) + 4(4^2+4+1) + 5(5^2+5+1)\) \(= 1(3) + 2(7) + 3(13) + 4(21) + 5(31)\) \(= 3 + 14 + 39 + 84 + 155\) \(= 295\)
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