ExamBro
ExamBro
AP EAMCET · Maths · Indefinite Integration

If \(\int \frac{x^4+1}{x^2+1} d x=A x^3+B x^2+C x+D \operatorname{Tan}^{-1} x+E\), then \(A+B+C+D=\)

  1. A \(\frac{3}{2}\)
  2. B \(\frac{4}{3}\)
  3. C \(\frac{1}{3}\)
  4. D \(\frac{2}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{4}{3}\)

Step-by-step Solution

Detailed explanation

\(\frac{x^4+1}{x^2+1} = x^2-1+\frac{2}{x^2+1}\) \(\int \left(x^2-1+\frac{2}{x^2+1}\right) d x = \frac{x^3}{3}-x+2\operatorname{Tan}^{-1} x+E\) \(A=\frac{1}{3}, B=0, C=-1, D=2\) \(A+B+C+D = \frac{1}{3}+0+(-1)+2 = \frac{4}{3}\)
From AP EAMCET
Explore more questions on app