AP EAMCET · Maths · Trigonometric Ratios & Identities
If \(\cosh (x-\log 3)=\sinh x\), then \(x=\)
- A \(\frac{1}{2} \log 3\)
- B \(\frac{1}{2} \log 6\)
- C \(\frac{1}{2} \log 5\)
- D \(\log 3\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2} \log 6\)
Step-by-step Solution
Detailed explanation
\(\cosh (x-\log 3)=\sinh x\) \(\begin{aligned} & \Rightarrow \frac{e^{x-\log 3}+e^{-(x-\log 3)}}{2}= \frac{e^x-e^{-x}}{2} \\ & {\left[\begin{array}{l}\cosh x=\frac{e^x+e^{-x}}{2} \\ \text { and } \sinh x=\frac{e^x-e^{-x}}{2}\end{array}\right] }\end{aligned}\)…
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