AP EAMCET · Maths · Probability
If 5 letters are to be placed in 5 -addressed envelopes, then the probability that at least one letter is placed in the wrongly addressed envelope is
- A \(\frac{1}{5}\)
- B \(\frac{1}{120}\)
- C \(\frac{4}{5}\)
- D \(\frac{119}{120}\)
Answer & Solution
Correct Answer
(D) \(\frac{119}{120}\)
Step-by-step Solution
Detailed explanation
Since, total number of ways in which 5 letters are placed in 5 -addressed envelopes \(=5!=120\) Now, the probability of all letters placed is correct placed \(=\frac{1}{120}\) So, P (at least one letters wrongly) \(=\) \(1-\frac{1}{120}=\frac{119}{120}\)
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