AP EAMCET · Maths · Circle
If \(x-4=0\) is the radical axis of two orthogonal circles out of which one is \(x^2+y^2=36\), then the centre of the other circles is
- A \((8,0)\)
- B \((9,0)\)
- C \((6,0)\)
- D \((12,0)\)
Answer & Solution
Correct Answer
(B) \((9,0)\)
Step-by-step Solution
Detailed explanation
Let equation of other circle be \(\begin{aligned} & S^{\prime} \equiv x^2+y^2+2 g x+2 f y+c=0 \\ & S \equiv x^2+y^2=36 \end{aligned}\) \(x^{\prime}-4=0 \text { is radicalaxis } \Rightarrow S^{\prime}=x^2+y^2-36+k(x-4)\) As circles are orthogonal…
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