AP EAMCET · Maths · Circle
If \(x^2+y^2-6 x-8 y+12=0\) and \(x^2+y^2-4 x+6 y+k=0\) cut orthogonally, then \(k=\)
- A \(-24\)
- B 24
- C –48
- D –42
Answer & Solution
Correct Answer
(A) \(-24\)
Step-by-step Solution
Detailed explanation
\(g_1 = -3, f_1 = -4, c_1 = 12\) \(g_2 = -2, f_2 = 3, c_2 = k\) \(2g_1g_2+2f_1f_2 = c_1+c_2\) \(2(-3)(-2) + 2(-4)(3) = 12+k\) \(12 - 24 = 12+k\) \(-12 = 12+k\) \(k = -24\)
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