AP EAMCET · Maths · Three Dimensional Geometry
If \(\mathrm{A}(1,2,3), \mathrm{B}(2,3,-1), \mathrm{C}(3,-1,-2)\) are the vertices of a triangle ABC, then the direction ratios of the bisector of \(\triangle \mathrm{ABC}\) are
- A \((4,1,1)\)
- B \((3,5,2)\)
- C \((1,4,1)\)
- D \((2,-3,-5)\)
Answer & Solution
Correct Answer
(D) \((2,-3,-5)\)
Step-by-step Solution
Detailed explanation
\(\vec{BA} = (1-2, 2-3, 3-(-1)) = (-1, -1, 4)\) \(\vec{BC} = (3-2, -1-3, -2-(-1)) = (1, -4, -1)\) \(|\vec{BA}| = \sqrt{(-1)^2 + (-1)^2 + 4^2} = \sqrt{18}\) \(|\vec{BC}| = \sqrt{1^2 + (-4)^2 + (-1)^2} = \sqrt{18}\)…
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