AP EAMCET · Maths · Indefinite Integration
If \(\frac{x^2-7 x+2}{x^4+3 x^2+4}=\frac{A x+B}{x^2+a x+2}+\frac{C x+D}{x^2+b x+2}\) and \(a>b\) then \(\mathrm{B}+\mathrm{D}=\)
- A \(a+b\)
- B \(2 a+b\)
- C \(a+2 b\)
- D \(a-b\)
Answer & Solution
Correct Answer
(B) \(2 a+b\)
Step-by-step Solution
Detailed explanation
\(\frac{x^2-7 x+2}{x^4+3 x^2+4}=\frac{A x+B}{x^2+a x+2}+\frac{C x+D}{x^2+b x+2}\) ...(i) \(\because \frac{x^2-7 x+2}{x^4+3 x^2+4}=\frac{x^2-7 x+2}{\left(x^2+x+2\right)\left(x^2-x+2\right)}\) The form of the partial fraction decomposition is :…
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