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AP EAMCET · Maths · Trigonometric Ratios & Identities

If \(\sec \theta+\tan \theta=\frac{1}{3}\), then the quadrant in which \(2 \theta\) lies is

  1. A \(1^{\text {st }}\) quadrant
  2. B \(2^{\text {nd }}\) quadrant
  3. C \(3^{\text {rd }}\) quadrant
  4. D \(4^{\text {th }}\) quadrant
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(C) \(3^{\text {rd }}\) quadrant

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\(\sec \theta+\tan \theta=\frac{1}{3}\) \(\qquad ....\mathrm{(i)}\) \(\frac{1}{\sec \theta-\tan \theta}=\frac{1}{3} \Rightarrow \sec \theta-\tan \theta=3\) \(\qquad ....\mathrm{(ii)}\) From (i) - (ii)…
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