AP EAMCET · Maths · Trigonometric Ratios & Identities
If \(\sec \theta+\tan \theta=\frac{1}{3}\), then the quadrant in which \(2 \theta\) lies is
- A \(1^{\text {st }}\) quadrant
- B \(2^{\text {nd }}\) quadrant
- C \(3^{\text {rd }}\) quadrant
- D \(4^{\text {th }}\) quadrant
Answer & Solution
Correct Answer
(C) \(3^{\text {rd }}\) quadrant
Step-by-step Solution
Detailed explanation
\(\sec \theta+\tan \theta=\frac{1}{3}\) \(\qquad ....\mathrm{(i)}\) \(\frac{1}{\sec \theta-\tan \theta}=\frac{1}{3} \Rightarrow \sec \theta-\tan \theta=3\) \(\qquad ....\mathrm{(ii)}\) From (i) - (ii)…
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