AP EAMCET · Maths · Pair of Lines
Find the equation of pair of straight lines that bisect the angles between the lines represented by \(a x^2+2 h x y+b y^2=0\).
- A \(\frac{x^2+y^2}{a+b}=\frac{x y}{h}\)
- B \(\frac{x^2+y^2}{a-b}=\frac{x y}{h}\)
- C \(\frac{x^2+y^2}{a-b}=\frac{h}{x y}\)
- D \(\frac{x^2-y^2}{a-b}=\frac{x y}{h}\)
Answer & Solution
Correct Answer
(D) \(\frac{x^2-y^2}{a-b}=\frac{x y}{h}\)
Step-by-step Solution
Detailed explanation
The equation of pair of straight lines that bisect the angles between the lines represented by \(\begin{aligned} a x^2+2 h x y+b y^2 & =0 \\ \text { is } \frac{x^2-y^2}{a-b} & =\frac{x y}{h}\end{aligned}\) Hence, option (d) is correct.
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