AP EAMCET · Chemistry · Ionic Equilibrium
A solution which is \(10^{-3} \mathrm{M}\) each in \(\mathrm{Mn}^{2+}, \mathrm{Fe}^{2+}, \mathrm{Zn}^{2+}\) and \(\mathrm{Hg}^{2+}\) is treated with \(10^{-16} \mathrm{M}\) sulphide ion. If the \(\mathrm{K}_{\mathrm{sp}}\) of MnS, FeS, \(\mathrm{ZnS}\) and \(\mathrm{HgS}\) are \(10^{-15}, 10^{-23}, 10^{-20}\) and \(10^{-54}\) respectively, which one will precipitate first?
- A \(\mathrm{FeS}\)
- B \(\mathrm{MnS}\)
- C \(\mathrm{HgS}\)
- D \(\mathrm{ZnS}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{HgS}\)
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