AP EAMCET · Chemistry · d and f Block Elements
The correct order of oxidizing power of the given ions is
- A \(\mathrm{VO}_2^{+} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{MnO}_4^{-}\)
- B \(\mathrm{VO}_2^{+} \lt \mathrm{MnO}_4^{-} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-}\)
- C \(\mathrm{MnO}_4^{-} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{VO}_2^{+}\)
- D \(\mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{VO}_2^{+} \lt \mathrm{MnO}_4^{-}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{VO}_2^{+} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{MnO}_4^{-}\)
Step-by-step Solution
Detailed explanation
In \(\mathrm{VO}_2^{+}, \mathrm{V}\) is in +3 oxidation state. \(\mathrm{Cr}_2 \mathrm{O}_7^{2-} \mathrm{Cr}\) is in +6 oxidation state. \(\mathrm{MnO}_4^{-} \mathrm{Mn}\) is in +7 oxidation state. Oxidising power means substance have more tendency to accept electron. Mn is in…
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