AP EAMCET · Maths · Probability
\(\mathrm{A}, \mathrm{B}, \mathrm{C}\) are mutually exclusive and exhaustive events of a random experiment and E is an event that occurs in conjunction with one of the events \(\mathrm{A}, \mathrm{B}, \mathrm{C}\). The conditional Probabilities of E given the happening of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) are respectively \(0.6,0.3\) and 0.1 . If \(\mathrm{P}(\mathrm{A})=0.30\) and \(\mathrm{P}(\mathrm{B})=\) 0.50 , then \(P(C \mid E)=\)
- A \(\frac{2}{35}\)
- B \(\frac{15}{35}\)
- C \(\frac{18}{35}\)
- D \(\frac{17}{35}\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{35}\)
Step-by-step Solution
Detailed explanation
\(P(\mathrm{~A})=0.30, P(\mathrm{~B})=0.50\) Since \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) are mutually exclusive and exhaustive \(\therefore P(A)+P(B)+P(C)=1\) \(\Rightarrow \mathrm{P}(\mathrm{C})=0.20, P(E / A)=0.6, P(E / B)=0.3, P(E / C)=0.1\) Now,…
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