AP EAMCET · Maths · Vector Algebra
If \(\vec{f}, \vec{g}, \vec{h}\) mutually orthogonal vectors of equal magnitudes, then the angle between the vectors \(\vec{f}+\vec{g}+\vec{h}\) and \(\vec{h}\) is
- A \(\cos ^{-1}\left(\frac{\sqrt{3}}{4}\right)\)
- B \(\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)\)
- C \(\pi-\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)\)
- D \(\pi-\cos ^{-1}\left(\frac{\sqrt{3}}{4}\right)\)
Answer & Solution
Correct Answer
(B) \(\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)\)
Step-by-step Solution
Detailed explanation
Given, \(\vec{f}, \vec{g}\) and \(\vec{h}\) are mutually orthogonal vector So, \(\vec{f} \cdot \vec{g}=\vec{g} \cdot \vec{h}=\vec{f} \cdot \vec{h}=0\). Let, \(|\vec{f}|=|\vec{g}|=|\vec{h}|=k\) Now,…
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