AP EAMCET · Maths · Straight Lines
If two sides of a triangle are given by \(3 x^2-5 x y+2 y^2=0\) and its orthocentre is \((2,1)\), then the equation of the third side of the triangle is
- A \(5 x-10 y+1=0\)
- B \(10 x+5 y-1=0\)
- C \(5 x-10 y=21\)
- D \(10 x+5 y=21\)
Answer & Solution
Correct Answer
(D) \(10 x+5 y=21\)
Step-by-step Solution
Detailed explanation
Given pair equation of two sides of triangle, \[ \begin{aligned} 3 x^2-5 x y+2 y^2 & =0 \\ \Rightarrow \quad(3 x-2 y)(x-y) & =0 \end{aligned} \] So, equation of sides are Perpendicular line to the Eq. (i) \(2 x+3 y+k=0\) which pass through the point \((2,1)\).…
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