AP EAMCET · Maths · Circle
If two diameters of a circle of circumference \(10 \pi\) lie along the lines \(2 x+3 y+1=0\) and \(3 x-y-4=0\), then the equation of circle is
- A \(x^2+y^2+2 x-2 y-23=0\)
- B \(x^2+y^2-2 x+2 y-23=0\)
- C \(x^2+y^2+2 x+2 y-23=0\)
- D \(x^2+y^2-2 x-2 y-23=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-2 x+2 y-23=0\)
Step-by-step Solution
Detailed explanation
Circumference of circle \(=10 \pi\) \[ \begin{aligned} 2 \pi r & =10 \pi \text { (let } r \text { be the radius of circle) } \\ r & =5 \end{aligned} \] Now, given that 2 diameters of circle lies along \[ 2 x+3 y+1=0 \text { and } 3 x-y-4=0 \] \(\therefore\) Centre is point of…
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