AP EAMCET · Maths · Statistics
If the sum of squares of the deviations from the mean of the data \(x_i,(i=1,2, \ldots, n)\) is \(n^2\), where \(\bar{x}\) is the mean of \(x_1\) 's, then the sum of squares of \(x_i\) 's is
- A \(4 n x^{-2}\)
- B \(3 \mathrm{nx}^{-2}\)
- C \(12 \mathrm{nx}^{-2}\)
- D \(2 n \mathrm{x}^{-2}\)
Answer & Solution
Correct Answer
(D) \(2 n \mathrm{x}^{-2}\)
Step-by-step Solution
Detailed explanation
Given, Sum of squares of deviations from the mean of data \(x_i=n \bar{x}^2\)…
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