AP EAMCET · Maths · Circle
The point of intersection of the direct common tangents drawn to the circles \((x+11)^2+(y-2)^2=225\) and \((x-11)^2+(y+2)^2=25\) is
- A \(\left(\frac{-11}{2}, 1\right)\)
- B \((-22,4)\)
- C \(\left(\frac{11}{2},-1\right)\)
- D \((22,-4)\)
Answer & Solution
Correct Answer
(D) \((22,-4)\)
Step-by-step Solution
Detailed explanation
The direct common tangents to two circles meet on the line of centres and divide it externally in the ratio of the radii centres of the two circles are \((-11,2)\) and \((11,-2)\) and their radii are 15 and 5 . \(\therefore\) Point of intersection…
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