AP EAMCET · Maths · Matrices
If the rank of the matrix \(A=\left[\begin{array}{cccc}1 & 2 & 1 & -1 \\ -1 & 2 & 3 & 5 \\ 0 & 1 & k & k\end{array}\right]\)is 2 and \(\mathrm{k}\) is a real number, then \(\mathrm{k}\) is a root of the following quadratic equation
- A \(x^2+3 x+2=0\)
- B \(x^2+x-2=0\)
- C \(x^2+x-6=0\)
- D \(x^2-x-6=0\)
Answer & Solution
Correct Answer
(B) \(x^2+x-2=0\)
Step-by-step Solution
Detailed explanation
\(A=\left[\begin{array}{cccc}1 & 2 & 1 & -1 \\ -1 & 2 & 3 & 5 \\ 0 & 1 & k & k\end{array}\right]\) Given, rank of \(\mathrm{A}=2\) \(\Rightarrow\) there must be 2 rows | columns which are linearly dependent. using Echelon transformation,…
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