AP EAMCET · Maths · Circle
The equation of the circle passing through \((0,0)\) and which makes intercepts \(a\) and \(b\) on the coordinate axes is
- A \(x^2+y^2+a x+b y=0\)
- B \(x^2+y^2+a x-b y=0\)
- C \(x^2+y^2-a x+b y=0\)
- D \(x^2+y^2-a x-b x=0\)
Answer & Solution
Correct Answer
(D) \(x^2+y^2-a x-b x=0\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {Centre }=\left(\frac{a}{2}, \frac{b}{2}\right) \\ & \text {Radius }=\frac{\sqrt{a^2+b^2}}{2} \end{aligned}\) Equation of circle…
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