AP EAMCET · Maths · Probability
The probability for a contractor to get a road contract is \(\frac{2}{9}\) and to get a building contract is \(\frac{5}{9}\), if the probability to get both the contract is \(\frac{1}{6}\), then what is the probability to get neither of these two contracts?
- A \(\frac{7}{9}\)
- B \(\frac{4}{9}\)
- C \(\frac{7}{18}\)
- D \(\frac{4}{18}\)
Answer & Solution
Correct Answer
(C) \(\frac{7}{18}\)
Step-by-step Solution
Detailed explanation
Let \(A\) be the event of getting a road contract and \(B\) be the event of getting a building contract. \(\therefore \quad P(A)=\frac{2}{9}, P(B)=\frac{5}{9}\) \(P(A \cap B)=\frac{1}{6}\) \(\therefore \quad P(A \cup B)=P(A)+P(B)-P(A \cap B)\)…
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