AP EAMCET · Maths · Vector Algebra
If the points with position vectors \((\alpha \hat{i}+10 \hat{j}+13 \hat{k})\), \((6 \hat{i}+11 \hat{j}+11 \hat{k}),\left(\frac{9}{2} \hat{i}+\beta \hat{j}-8 \hat{k}\right)\) are collinear then \((19 \alpha-6 \beta)^2=\)
- A \(16\)
- B \(36\)
- C \(25\)
- D \(49\)
Answer & Solution
Correct Answer
(B) \(36\)
Step-by-step Solution
Detailed explanation
Since, \((\alpha \hat{i}+10 \hat{j}+13 \hat{k}),(b \hat{i}+11 \hat{j}+11 \hat{k})\) and \(\left(\frac{9}{2} \hat{i}+\beta \hat{j}-8 \hat{k}\right)\) are collinear. So,…
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