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AP EAMCET · Maths · Quadratic Equation

If \(\alpha\) and \(\beta(\alpha>\beta)\) are the multiple roots of the equation \(4 x^4+4 x^3-23 x^2-12 x\) \(+36=0\), then \(2 \alpha-\beta=\)

  1. A \(-1\)
  2. B \(3\)
  3. C \(5\)
  4. D \(-7\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5\)

Step-by-step Solution

Detailed explanation

\(P'(x) = 16x^3+12x^2-46x-12\). Solving \(P'(x)=0\) yields roots \(x=-2, x=\frac{3}{2}, x=-\frac{1}{4}\). Substituting into \(P(x)\): \(P(-2)=0\) and \(P(\frac{3}{2})=0\). Thus, \(\alpha=\frac{3}{2}\) and \(\beta=-2\) (since \(\alpha>\beta\)).…