AP EAMCET · PHYSICS · Dual Nature of Matter
Light with an energy flux of \(9 \mathrm{Wcm}^{-2}\) falls on a nonreflecting surface at normal incidence. If the surface has an area of \(20 \mathrm{~cm}^2\). The total momentum delivered for complete absorption in one hour is
- A \(2.16 \times 10^{-4} \mathrm{kgms}^{-1}\)
- B \(1.16 \times 10^{-3} \mathrm{kgms}^{-1}\)
- C \(2.16 \times 10^{-3} \mathrm{kgms}^{-1}\)
- D \(3.16 \times 10^{-4} \mathrm{kgms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(2.16 \times 10^{-3} \mathrm{kgms}^{-1}\)
Step-by-step Solution
Detailed explanation
We have total momentum as \(\Delta p=\left(\frac{I A}{c}\right) t\) for non reflecting surface, \(\begin{aligned} & \Delta p=\left(\frac{9 \times 10^4 \times 20 \times 10^{-4}}{3 \times 10^8} \times 3600\right) \\ & =216 \times 10^{-3} \mathrm{kgms}^{-1} \end{aligned}\)
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